Bug 1223387 (CVE-2024-26924) - VUL-0: CVE-2024-26924: kernel: netfilter: nft_set_pipapo: do not free live element
Summary: VUL-0: CVE-2024-26924: kernel: netfilter: nft_set_pipapo: do not free live el...
Status: NEW
Alias: CVE-2024-26924
Product: SUSE Security Incidents
Classification: Novell Products
Component: Incidents (show other bugs)
Version: unspecified
Hardware: Other Other
: P3 - Medium : Normal
Target Milestone: ---
Assignee: Michal Kubeček
QA Contact: Security Team bot
URL: https://smash.suse.de/issue/403112/
Whiteboard: CVSSv3.1:SUSE:CVE-2024-26924:5.5:(AV:...
Keywords:
Depends on:
Blocks:
 
Reported: 2024-04-25 10:21 UTC by SMASH SMASH
Modified: 2024-07-04 09:26 UTC (History)
3 users (show)

See Also:
Found By: Security Response Team
Services Priority:
Business Priority:
Blocker: ---
Marketing QA Status: ---
IT Deployment: ---


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Description SMASH SMASH 2024-04-25 10:21:35 UTC
In the Linux kernel, the following vulnerability has been resolved:

netfilter: nft_set_pipapo: do not free live element

Pablo reports a crash with large batches of elements with a
back-to-back add/remove pattern.  Quoting Pablo:

  add_elem("00000000") timeout 100 ms
  ...
  add_elem("0000000X") timeout 100 ms
  del_elem("0000000X") <---------------- delete one that was just added
  ...
  add_elem("00005000") timeout 100 ms

  1) nft_pipapo_remove() removes element 0000000X
  Then, KASAN shows a splat.

Looking at the remove function there is a chance that we will drop a
rule that maps to a non-deactivated element.

Removal happens in two steps, first we do a lookup for key k and return the
to-be-removed element and mark it as inactive in the next generation.
Then, in a second step, the element gets removed from the set/map.

The _remove function does not work correctly if we have more than one
element that share the same key.

This can happen if we insert an element into a set when the set already
holds an element with same key, but the element mapping to the existing
key has timed out or is not active in the next generation.

In such case its possible that removal will unmap the wrong element.
If this happens, we will leak the non-deactivated element, it becomes
unreachable.

The element that got deactivated (and will be freed later) will
remain reachable in the set data structure, this can result in
a crash when such an element is retrieved during lookup (stale
pointer).

Add a check that the fully matching key does in fact map to the element
that we have marked as inactive in the deactivation step.
If not, we need to continue searching.

Add a bug/warn trap at the end of the function as well, the remove
function must not ever be called with an invisible/unreachable/non-existent
element.

v2: avoid uneeded temporary variable (Stefano)

References:
http://web.nvd.nist.gov/view/vuln/detail?vulnId=CVE-2024-26924
https://git.kernel.org/pub/scm/linux/security/vulns.git/plain/cve/published/2024/CVE-2024-26924.mbox
https://git.kernel.org/stable/c/3cfc9ec039af60dbd8965ae085b2c2ccdcfbe1cc
https://www.cve.org/CVERecord?id=CVE-2024-26924